The payout for a street bet in roulette, where a player wagers on three consecutive numbers in a row, is 11 to 1. If the ball lands on any of the three chosen numbers, the player receives 11 times their original bet in winnings, plus the return of their initial wager. This payout offers a middle ground between the higher-risk, higher-reward single-number bets and the lower-risk, lower-reward outside bets.