Would you mind explaining the pass line bet's winning chances?

[ProGambler]

In the dice game of craps, the pass line bet is a common wager. By placing this wager, you are effectively wagering on whether the shooter will roll a 7 or an 11 on the come-out roll, or whether they will roll the point number twice before rolling a 7. The first roll of the dice that is neither a 7 or an 11 determines the point total.

The established point total affects how likely it is that a pass line wager will win. If the point is 4 or 10, the odds of winning are 2:1 against, which means that you will win once for every two losses.

 

[CR7]

three wins, you will experience two losses. If the point is 6 or 8, the odds of winning are 6:5, which means that for every six wins, you will experience five losses.

Additionally, if the shooter rolls a 2, 3, or 12 on the come-out roll, you will lose your pass line bet. These numbers are referred to as "craps." The house edge on craps is approximately 1.41%, meaning that over the long run, the house will win approximately 1.41% of the wagers placed on the pass line.

On the other hand, if the shooter rolls a 7 or 11 on the come-out roll, you will win your pass line bet. These numbers are referred to as "natural" rolls. The odds of rolling a natural are approximately 22.22%, which means that you will win slightly less than 1 in 5 times on the come-out roll.

It's important to note that while the pass line bet offers relatively good odds for the player, it is still a game of chance and there is always a risk of losing money. Players should never gamble more than they can afford to lose and should always practice responsible gambling habits.